2^n+2^2-n=5

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Solution for 2^n+2^2-n=5 equation: 



2^n+2^2-n=5

We move all terms to the left:

2^n+2^2-n-(5)=0

determiningTheFunctionDomain
2^n-n-5+2^2=0

We add all the numbers together, and all the variables

-1n+2^n-1=0

We move all terms containing n to the left, all other terms to the right

-1n+2^n=1

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